Guess Number Higher or Lower II
Question
We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I'll tell you whether the number I picked is higher or lower.
However, when you guess a particular number x
, and you guess wrong, you pay $x
. You win the game when you guess the number I picked.
Example:
n = 10, I pick 8.
First round: You guess 5, I tell you that it's higher. You pay $5.
Second round: You guess 7, I tell you that it's higher. You pay $7.
Third round: You guess 9, I tell you that it's lower. You pay $9.
Game over. 8 is the number I picked.
You end up paying $5 + $7 + $9 = $21.
Given a particular n ≥ 1
, find out how much money you need to have to guarantee a win.
Tags
- Dynamic Programming
- Minmax
Thought
This problem is harder than its easier one: Guess Number Higher or Lower, because this question requires the dynamic programming.
We can consider this question as a gaming problem that each player wants to defeat his or her opponent. For the gaming problem, we usually use the Minmax algorithm for Dynamic Programming.
Code
class Solution(object):
def getMoneyAmount(self, n):
"""
:type n: int
:rtype: int
"""
# dynamic programming
dp_table = [[0] * (n + 1) for _ in range(n + 1)]
for lo in xrange(n, 0, -1):
for hi in xrange(lo + 1, n + 1):
dp_table[lo][hi] = min(i + max(dp_table[lo][i - 1], dp_table[i + 1][hi]) for i in xrange(lo, hi))
return dp_table[1][n]