Human Traffic of Stadium

Question

X city built a new stadium, each day many people visit it and the stats are saved as these columns: id, date, people

Please write a query to display the records which have 3 or more consecutive rows and the amount of people more than 100(inclusive).

For example, the table stadium:

+------+------------+-----------+
| id   | date       | people    |
+------+------------+-----------+
| 1    | 2017-01-01 | 10        |
| 2    | 2017-01-02 | 109       |
| 3    | 2017-01-03 | 150       |
| 4    | 2017-01-04 | 99        |
| 5    | 2017-01-05 | 145       |
| 6    | 2017-01-06 | 1455      |
| 7    | 2017-01-07 | 199       |
| 8    | 2017-01-08 | 188       |
+------+------------+-----------+

For the sample data above, the output is:

+------+------------+-----------+
| id   | date       | people    |
+------+------------+-----------+
| 5    | 2017-01-05 | 145       |
| 6    | 2017-01-06 | 1455      |
| 7    | 2017-01-07 | 199       |
| 8    | 2017-01-08 | 188       |
+------+------------+-----------+

Note: Each day only have one row record, and the dates are increasing with id increasing.

Tags

  • SQL

Thought

reference: https://discuss.leetcode.com/topic/91926/solution-using-join

Use LEFT JOIN here.

Code

# Write your MySQL query statement below
SELECT t.* FROM stadium AS t
    LEFT JOIN stadium AS p1 ON t.id - 1 = p1.id
    LEFT JOIN stadium AS p2 ON t.id - 2 = p2.id
    LEFT JOIN stadium AS n1 ON t.id + 1 = n1.id
    LEFT JOIN stadium AS n2 ON t.id + 2 = n2.id
WHERE (t.people >= 100 AND p1.people >= 100 AND p2.people >= 100)
    OR (t.people >= 100 AND n1.people >= 100 AND n2.people >= 100)
    OR (t.people >= 100 AND p1.people >= 100 AND n1.people >= 100)
ORDER BY t.id;

results matching ""

    No results matching ""