Search in Rotated Sorted Array II

Question

Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Write a function to determine if a given target is in the array.

The array may contain duplicates.

Tags

• Array
• Binary Search

Thought

Similar to the question Search in Rotated Sorted Array, but we need to pay attention to the boundary conditions.

Code

class Solution(object):
    def search(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: bool
        """
        left = 0
        right = len(nums) - 1
        while left <= right:
            mid = (left + right) / 2
            if nums[mid] == target:
                return True
            if nums[left] == nums[mid] == nums[right]:
                left += 1
                right -= 1
            elif nums[left] <= nums[mid]:
                if nums[left] <= target < nums[mid]:
                    right = mid - 1
                else:
                    left = mid + 1
            else:
                if nums[mid] < target <= nums[right]:
                    left = mid + 1
                else:
                    right = mid - 1
        return False