Search Insert Position

Question

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,6], 2 → 1 [1,3,5,6], 7 → 4 [1,3,5,6], 0 → 0

Tags

• Array
• Binary Search

Thought

Use the binary sesarch here.

Code

class Solution(object):
    def searchInsert(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: int
        """
        start, end = 0, len(nums) - 1
        while start <= end:
            mid = (start + end) / 2
            if nums[mid] == target:
                return mid
            elif nums[mid] > target:
                end = mid - 1
            else:
                start = mid + 1
        return start